Question

If p(x)= x²+5x-2 then p (3) +p (2) +p (0)=?​

Answer 1

Step-by-step explanation:

Question ➡

P(x) = {x}^{2} + 5x + 2P(x)=x

2

+5x+2

Answer ➡

To find the values of P(3)+P(2)+P(0) ! For this we have to find the values separately.

Substitute 3 in place of "x"

\begin{gathered}P(x) = {x}^{2} + 5x + 2 \\ P(3) = {3}^{2} + 5(3) + 2 \\ P(3) = 9 + 15 + 2 \\ P(3) = 26\end{gathered}

P(x)=x

2

+5x+2

P(3)=3

2

+5(3)+2

P(3)=9+15+2

P(3)=26

Hence the value of p(3) = 26

Now, substitute 2 in place of "x"

\begin{gathered}P(x) = {x}^{2} + 5x + 2 \\ P(2) = {2}^{2} + 5(2) + 2 \\ P(2) = 4 + 10 + 2 \\ P(2) = 16\end{gathered}

P(x)=x

2

+5x+2

P(2)=2

2

+5(2)+2

P(2)=4+10+2

P(2)=16

Hence the value of p(2) = 16

Now, substitute 0 in place of "x"

\begin{gathered}P(x) = {x}^{2} + 5x + 2 \\ P(0) = {0}^{2} + 5(0) + 2 \\ P(0) = 0 + 0 + 2 \\ P(0) = 2\end{gathered}

P(x)=x

2

+5x+2

P(0)=0

2

+5(0)+2

P(0)=0+0+2

P(0)=2

Hence the value of p(0) = 2

Now to find the value of P(3)+P(2)+P(0)

= P(3)+P(2)+P(0)

= 26+16+2

= 44

Therefore value of P(3)+P(2)+P(0) is 44.