If p(x)=x2+5x+2,then p(3)+p(2)+p(0)is
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Let x = 3
p (3) = 2(3)+5(3)+2
p (3) = 6+15+2
p (3) = 23
Let x = 2
p (2) = 2(2)+5(2)+2
p (2) = 4+10+2
p (2) = 16
Let x = 0
p (0) = 2(0)+5(0)+2
p (0) = 0+0+2
p (0) = 0
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Answer:
1.p(3)=2*3+5*3+2=23
2.p(2)=2*2+5*2+2=16
3.p(0)=2*0+5*0+2=2
so sum
p(3)+p(2)+p(0)=41
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