If p(x) = x² – 5x + 4 and q(x) = x² + 1, then p(1) × q(1) is equal to
Answers
Answered by
1
Answer:
p(1) = 1² - 5(1) + 4
=> p (1) = 1 -5+4
=> p(1) = -4+4
=> p(1) = 0
=> p(1) × q(1) = 0 × q(1)
=> p(1) × q(1) = 0
Answered by
1
Answer:
p(x)=1^2-5×1+4
=1-5+4
=5-5
=0
And
q(x)=x^2+1
=1^2+1
=1+1
=2
so,
p(1)×q(1)=0×2
=0
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