Question

If p(x) =x2-5x+4 and q (x) = x3 +1 find the value of (P) (1) ×q (1)

Answer 1

Answer:

p(x)=x2-5x+4

p(1)=(1)2-5(1)+4

=1-5+4

=5-5

p(1)=0

q(x)=x3+1

q(1)=(1)3+1

=1+1

q(1) =2

Step-by-step explanation:

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