Question

If p(x)=x2-5x-6, then find the value of p(3)

Answer 1

Answer:

$\huge\red{\boxed{\bold{Answer}}}$

$p(3) = {(3)}^{2} - 5(3) - 6 \\ \\ = 9 - 15 - 6 \\ \\ = 9 - 21 \\ \\ = - 12$

Answer 2

Hey mate!!

p(x)=x^2-5x-6

p(1)=1^2-5(1)-6

=1-5-6

=-4-6

=-10

p(2)=2^2-5(2)-6

=4-10-6

=-6-6

=-12

p(3)=3^2-5(3)-6

=9-15-6

=-6-6

=-12

p(0)=0^2-5(0)-6

=-6

p(-1)=-1^2-5(-1)-6

=1+5-6

=0

p(-2)=-2^2-5(-2)-6

=4+10-6

=14-6

=8

p(-3)=-3^2-5(-3)-6

=9+15-6

=24-6

=18

hope it helps!!