Question

If p(x) = x² - 5x - 6, then find the values of p(1), p(2), p(0), p(-1), p(-3).​

Answer 1

given p(x)=x^2-5x-6

p(1)=(1)^2-5(1)-6=1-5-6= -10

p(2)=(2)^2-5(2)-6=4-10-6= -12

p(0)=0-0-6= -6

p(-1)=(-1)^2-5(-1)-6=1+5-6=0

p(-3)=(-3)^2-5(-3)-6=9+15-6= 18