Question

If p(x) = x2 – 5x - 6, then find the values of p(1), p(2), p(O), p(-1),p(-3).​

Answer 1

Answer:

p(0) = (0)2-5(0)-6

p(0) = 0-0-6

p(0) = -6

p(1) = (1)2-5(1)-6

1-5-6

1-11 = -10

p(2) = (2)2-5(2)-6

4-10-6

-6-6 = -12

p(-1) = (-1)2-5(-1)-6

1+5-6 = 0

p(-3) = (-3)2-5(-3)-6

9+15-6

24-6 = 18

Answer 2

Given :

• $\sf P(x) = x^2 - 5x - 6$

To Find :

• P(1)
• P(2)
• P(0)
• P(-1)
• P(-3)

Solution :

Substitute the values directly in place of x.

${\rightarrow \sf P(x) = x^2-5x-6}$

${\rightarrow \sf P(1)=(1)^2-5(1)-6}$

${\rightarrow \sf (1)-5-6}$

${\rightarrow 1-11}$

${\rightarrow \sf \boxed{\sf P(1) = -10}}$

${\rightarrow \sf P(x) = x^2-5x-6}$

${\rightarrow \sf P(2)=(2)^2-5(2)-6}$

${\rightarrow \sf (4)-10-6}$

${\rightarrow 4-16}$

${\rightarrow \boxed{\sf P(2)=-12}}$

${\rightarrow \sf P(x) = x^2-5x-6}$

${\rightarrow \sf P(0)=(0)^2-5(0)-6}$

${\rightarrow \sf (0)-0-6}$

${\rightarrow 0-6}$

${\rightarrow \boxed{\sf P(0)=-6}}$

${\rightarrow \sf P(x) = x^2-5x-6}$

${\rightarrow \sf P(-1)=(-1)^2-5(-1)-6}$

${\rightarrow \sf (1)+5-6}$

${\rightarrow 6-6}$

${\rightarrow \boxed{\sf P(-1)=0}}$

${\rightarrow \sf P(x) = x^2-5x-6}$

${\rightarrow \sf P(-3)=(-3)^2-5(-3)-6}$

${\rightarrow \sf (9)+15-6}$

${\rightarrow 24-6}$

${\rightarrow \boxed{\sf P(-4)= 18}}$

Required Answer :

• P(1) = -10
• P(2) = -12
• P(0) = -6
• P(-1) = 0
• P(-3) = 18