Question

If p(x) = x² – 5x +7, evaluate : p(2) – p(-1) + p( ⅓)​

Answer 1

p(2) -p(-1) + p(1/3) = -59/9

Step-by-step explanation:

p(2) = 2² - 5(2) + 7

= 4-10+7

= 11-10 = 1

p(-1) = (-1)² - 5(-1) + 7

= 1+5+7 = 13

p(1/3) = (1/3)² -5(1/3) +7

= 1/9 - 5/3 + 7

= 1/9 - 15/9 + 7

= -14/9 + 63/9

= 49/9

here p(2) - p(-1) + p(1/3)

= 1-13+49/9

= -12+49/9

= -108+49/9

= -59/9

Answer 2

p(x)=x²-5x+7

then P(2)=2²-5(2)+7

4-10+7

=1

P(-1)=(-1)²-5(-1)+7

1+5+7

=13

P(1/3)=(1/3)²-5(1/3)+7

1/9-5/3+7

= (1-15+63)/9

=49/9

p(2)-p(-1)+p(1/3)

=1+13+49/9

=(9+117+49)/9

=175/9