Question

If p(x) = x2 - 6x + 3 then find the values of p(-1), p(2).​

Answer 1

Answer:

p(x)= x²-6x+3

firstly putting x=-1

(-1)²-6(-1)+3

=1+6+3

=10

second putting x=2

= 2²-6×2+3

=4-12+3

=5

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Answer 2

Answer:

$p(x) = x {}^{2} - 6x + 3 \\ p( - 1) = ( - 1) {}^{2} - 6 \times ( - 1) + 3 \\ p( - 1) = 1 + 6 + 3 \\ p( - 1) = 10 \\ \\ p(x) = x {}^{2} - 6x + 3 \\ p(2) = 2 {}^{2} - 6 \times 2 + 3 \\ p(2) = 4 - 12 + 3 \\ p(2) = 5$