Math, asked by bharathinadikattu, 9 months ago

If p(x)=x2-6x-5 then find p(0), p(-1).​

Answers

Answered by chrissy777
1

Answer:

p(x)=x^2 - 6x - 5

p(0) = 0^2-6(0)-5

      = 0-0-5

      = - 5

p(x)=x^2-6x-5

p(-1) = (-1)^2 - 6(-1) - 5

      = 1 - 7-5

      = -6-5

     = -11

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