If P(x)=x²-6x+7 then find p(3-root2)
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here p= (3-√2)^2-6(3-√2)+7
=9+2-6√2-18+6√2+7
=0
hope it's gonna help u buddy
=9+2-6√2-18+6√2+7
=0
hope it's gonna help u buddy
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some late because I do first khata after share
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