Question

If p(x) = x2 - 6x + 8. then find the value of p (2) +p (1)-p (1/2)​

Answer 1

Answer:

this question is quite simple

first write the equation

${x}^{2} - 6x + 8$

now substitute the values of x given in the question

first p(2)

${(2) }^{2} - 6(2) + 8 \\ = 4 - 12 + 8 \\ = 12 - 12 = 0$

second p(1)

${(1)}^{2} - 6(1) + 8 \\ = 1 - 6 + 8 \\ = 9 - 6 = 3$

now p(1/2)

${ \frac{1}{2} }^{2} - 6( \frac{1}{2} ) + 8 \\ = \frac{1}{4} - 3 + 8 \\ = 5 + \frac{1}{4} = \frac{20 + 1}{4} = \frac{21}{4}$

now put these values in the question

Step-by-step explanation:

0+3-21/4

3-21/4

12-21/4

-9/4

I hope it is helpful

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