Question

If p(x) = x²+kx+9 and p(-2) =4 the k=

Answer 1

⇒ The given quadratic equation is x

2

−kx+9=0, comparing it with ax

2

+bx+c=0

∴ We get, a=1b=−k,c=9

⇒ It is given that roots are real and distinct.

∴ b

2

−4ac≥0

⇒ (−k)

2

−4(1)(9)≥0

⇒ k

2

−36≥0

⇒ k

2

≥36

⇒ k≥6 or k≤−6

∴ We can see values of k given in question are correct.

Answer 2

Answer:

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