Question

If p(x)=x2-x-1 find the value of p(x) if p(x)=-1? a) -3 b) 1 c) -1 please give me the answer it's urgent​

Answer 1

Answer:

\text{Hence, the value is }\frac{1}{2}(p(-1)+p(1))\text{ is 0.}Hence, the value is

2

1

(p(−1)+p(1)) is 0.

Step-by-step explanation:

\text{Given the polynomial }p(x)=x^3-x^2+x+1Given the polynomial p(x)=x

3

−x

2

+x+1

\text{we have to find the value of }\frac{1}{2}(p(-1)+p(1))we have to find the value of

2

1

(p(−1)+p(1))

p(x)=x^3-x^2+x+1p(x)=x

3

−x

2

+x+1

Put x=-1 and x=1

p(-1)=(-1)^3-(-1)^2+(-1)+1=-1-1-1+1=-2p(−1)=(−1)

3

−(−1)

2

+(−1)+1=−1−1−1+1=−2

p(1)=(1)^3-(1)^2+(1)+1=1-1+1+1=2p(1)=(1)

3

−(1)

2

+(1)+1=1−1+1+1=2

\frac{1}{2}(p(-1)+p(1))

2

1

(p(−1)+p(1))

=\frac{1}{2}(-2+2)=0=

2

1

(−2+2)=0

\text{Hence, the value is }\frac{1}{2}(p(-1)+p(1))\text{ is 0.}Hence, the value is

2

1

(p(−1)+p(1)) is 0.

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Answer 2

Answer:

Constrained Maximize(expr, { x1(low1, up1), x2(low2, up2), . ... Finds the values for the x arguments, specified as a list, ... the value of which to calculate the desirability.