Question

If p(x) = x2 – x + 1 then find the values of p( –1), p(0), p(1) and (2)​

Answer 1

Answer:

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Step-by-step explanation:

p (1) = (1)^2-(1)+1

1-1+1

1

P (-1) = (-1)^2-(-1)+1

1+1+1

3

p (0)=(0)^2-(0)+1

0-0+1

1

just put the values of x

Answer 2

Answer:

p(x) = x2 – x + 1

p( –1)=1-1+1

p(-1)=1

p(1)

hope it helps