Question

If P(x) = x² - x +1 then find the values of P(-1), p(0) P(I) and p (2)​

Answer 1

Step-by-step explanation:

p(-1)= 1-(-1)+1= 1+1+1=3

p(0)= 1

p(1)= 1

p(2)= 4-2+1= 3

Answer 2

Step-by-step explanation:

Given :-

P(x) = x²-x+1

To find :-

Find the values of P(-1), P(0), P(I) and P (2)?

Solution :-

Given polynomial is P(x) = x²-x+1 -----(1)

i) Put x =-1 in (1) then

=> P(-1) = (-1)²-(-1)+1

=> P(-1) = 1+1+1

=> P(-1) = 3

ii) Put x = 0in (1) then

=> P(0) = (0)²-(0)+1

=> P(0) = 0+0+1

=> P(0) = 1

iii) Put x = 1 in (1) then

=> P(1) = (1)²-(1)+1

=> P(1) = 1-1+1

=> P(1) = 2-1

=> P(1) = 1

iv) Put x = 2 in (1) then

=> P(2) = (2)²-(2)+1

=> P(2) = 4-2+1

=> P(2) = 5-2

=> P(2) = 3

Answer:-

The value of P(-1) = 3

P(0) = 1

P(1) = 1

P(2) = 3