Question

if p(x)=x²+x+3.then p(-1)is:​

Answer 1

$p(x) = {x}^{2} + x + 3$

$\sf{p( - 1) = { (- 1)}^{2} + ( - 1) + 3}$

$\sf{p( - 1) = 1 - 1 + 3}$

$\sf{p( - 1) = 3}$

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