Math, asked by jerryjam5984, 9 months ago

If p(x) = x2 - x - 3 then the value of p(1) - p(0) is

Answers

Answered by zahaansajid
3

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p(x) = x² - x - 3

p(1) = 1² - 1 - 3

       = 1 - 1 - 3

       = -3

p(0) = 0² - 0 - 3

       = -3

Therefore,

p(1) - p(0) = -3 - (-3)

                 = -3 + 3

                 = 0

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Answered by Sesaradi
0

Answer:

Step-by-step explanation:

P(1) = 1^2-1-3=1-1-3= -3

P(0) =0-0-3= -3

P(1) -P(0) = -3-(-3) = -3+3= 0

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