If p(x) = x2-x-6find the zeroes of P(x)
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Given here
if p(x) =x²-x-6
find the zeroes of p(x)
Solution :--
p(x)= x²-x-6
= x²-3x+2x-6
= x(x-3)+2(x-3)
= (x+2)(x-3)
so,
Zeroes will be ,
x+2=0, or x-3=0
x= -2, or. x= 3
Thus:--
zeroes of p(x) will be
-2, 3
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