Question

If p(x) = x2+ x, find the value of p(x) + p(-x)

Answer 1

Answer:

$p(x) + p( - x) = 2 {x}^{2}$

Step-by-step explanation:

Given :

$p(x) = {x}^{2} + x$

Therefore,

$p( - x) = ( { - x)}^{2} + ( - x) \\ therefore \: \: p(x) + \: p( - x) \: = \\ ({x}^{2} + x) + ( { - x)}^{2} - x \\ = {x}^{2} + x + {x}^{2} - x \\ = 2 {x}^{2}$

Hence, the answer.