If p(x)=x³- 1 then the value of P(1) + P(-1) is?
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Answered by
54
P(1)= 1³-1=1-1=0
P(-1)=(-1)³-1= -1-1=-2
therefore,P(1)+P(-1)=0+(-2)= -2
P(-1)=(-1)³-1= -1-1=-2
therefore,P(1)+P(-1)=0+(-2)= -2
drishti221016:
thanx
Answered by
64
p(x)=x³-1
p(1)=(1)³-1
p(1)=1-1=0
p(-1)=(-1)³-1
p(-1)=-1-1= -2
Therefore, p(1)=0,p(-1)=-2
p(1)+p(-1)=0+(-2)= -2
hope it helps
p(1)=(1)³-1
p(1)=1-1=0
p(-1)=(-1)³-1
p(-1)=-1-1= -2
Therefore, p(1)=0,p(-1)=-2
p(1)+p(-1)=0+(-2)= -2
hope it helps
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