If p(x)= x3-2x2+kx+5 is divided by (x-2), the remainder is 11. find k. hence find all the zeroes of x3+kx2+3x+1. plssss answer FAASSSTTTTT
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0=x-2
x=2
p (x) = x3 -2x2+ kx +5
p (2)= 2×3 - 2×2×2 +k×2+5
0 = 6-8+2k+5
2k= -3
k=-3÷2
0=x3 +kx2+3x+1
0=3x+3x+3x+1
12x=-1
x=-1÷12
x=2
p (x) = x3 -2x2+ kx +5
p (2)= 2×3 - 2×2×2 +k×2+5
0 = 6-8+2k+5
2k= -3
k=-3÷2
0=x3 +kx2+3x+1
0=3x+3x+3x+1
12x=-1
x=-1÷12
rajeshbhatia19pefbch:
see my answer is right or not
kiddo, it isn't right at all.
so what is right
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