Question

If P(x)=x³ −2x² + x − 1, the value of P(x) is​

Answer 1

Answer with solution:

p(x)= x³ - 2x² + x + 1

p(0) = 0³ - 2(0)² + 0 + 1

p(0) = 0 - 2(0) + 1

p(0) = - 0 + 1

p(0) = 1

p(1) = 1³ - 2(1)² + 1 + 1

p(1) = 1 - 2(1) + 2

p(1) = 1 - 2 + 2

p(1) = 1

p(0) × p(1) = 1 × 1

p(0) × p(1) = 1

Answer 2

Following are the steps for getting the answer:

Given:

P(x)=x³ −2x² + x − 1

To find:

the value of P(x)

Solution:

let ,

P(x)=P(0)

put x= 0 in the equation

P(0)=0³-2(0)²+0-1

P(0)=0-0-1

P(0)=-1

Now,

P(x)=P(1)

P(1)=1³-2(1)²+1-1

P(1)=1-2+0

p(1)=-1

Now, p(0)-p(1)=-1+(-1)

p(0)-p(1)=-2

hence, P(x)=x³ −2x² + x − 1, the value of P(x) is -2 if x= 1 and x=0