Question

If p(x)=x³+2x²-x+1 then 2p(0) -p(-1) is ______ *

1
-1
0
3​

Answer 1

Answer is 0

$2p(0) = 2( {0}^{ 3} + 2 \times {0}^{2} + 1) \\ = 2 \\ \\ p( - 1) = {( - 1)}^{3} + 2 \times {( - 1)}^{2} + 1 \\ = 2 \\ \\ = 2p(0) - p (- 1 ) \\ = 2 - 2 \\ = 0$

Answer 2

Answer:

2p(0)=2(0

3

+2×0

2

+1)

=2

p(−1)=(−1)

3

+2×(−1)

2

+1

=2

=2p(0)−p(−1)

=2−2

=0

plese brainlest answer me