Question

If p(x)= x3-2x2+x+1 then p(0) ×p(1)​

Answer 1

ANSWER:

• The value of p(0) × p(1) = 1.

GIVEN:

• p(x)= x³ - 2x² + x + 1.

TO FIND:

• The value of p(0) × p(1).

EXPLANATION:

p(x)= x³ - 2x² + x + 1

p(0) = 0³ - 2(0)² + 0 + 1

p(0) = 0 - 2(0) + 1

p(0) = - 0 + 1

p(0) = 1

p(1) = 1³ - 2(1)² + 1 + 1

p(1) = 1 - 2(1) + 2

p(1) = 1 - 2 + 2

p(1) = 1

p(0) × p(1) = 1 × 1

p(0) × p(1) = 1

HENCE THE VALUE OF P(0) × P(1) = 1.

Answer 2

Answer:

-5 is correct answer

Step-by-step explanation:

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