Question

if p(x) x3 +3x2 -2x+4 then find the value of p(2)+p(-2)-p(0)​

Answer 1

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p(x) x3 +3x2 -2x+4

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when x=2

$p(2) = 2 {}^{3} + 3 \times 2 {}^{2} - 2 \times 2 + 4 \\ p(2) = 8 + 12 \\ p(2) = 20$

when x=-2

$p( - 2) = - 2 {}^{3} + 3 \times - 2 {}^{2} - 2 \times - 2 + 4 \\ p( - 2) = - 8 + 12 + 4 + 4 \\ p( - 2) = 12$

when x=0

$p( 0) = {0}^{3} + 3 \times 0 {}^{2} - 2 \times 0 + 4 \\ p( 0) = 4$

Answer 2

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$\large\underline{ \underline{ \green{ \bold{solution}}}} = >$

given polynomial=

p(x) x3 +3x2 -2x+4-----1

when we put x=2 in 1

$p(2) = 2 {}^{3} + 3 \times 2 {}^{2} - 2 \times 2 + 4 \\ p(2) = 8 + 12 \\ p(2) = 20$

when we put x=-2 in 1

$p( - 2) = - 2 {}^{3} + 3 \times - 2 {}^{2} - 2 \times - 2 + 4 \\ p( - 2) = - 8 + 12 + 4 + 4 \\ p( - 2) = 12$

when we put x=0 in 1

$p( 0) = {0}^{3} + 3 \times 0 {}^{2} - 2 \times 0 + 4 \\ p( 0) = 4$