if p(x)=x3-3x2+2x find p(0),p(1),p(2) what do you conclude?
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Answer:
Step-by-step explanation:
Step-by-step explanation:
p(x)=x^3-3x^2+2x
p(0) =0^3-3×0^2+2×0
=0-0+0
=0
p(1)=1^3-3×1^2+2×1
=1-3×1+2
=1-3+2
=3-3
=0
p(2)=2^3-3×2^2+2×2
=8-12+4
=12-12
=0
therefore they are zero polynomials
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