Question

if p(x)=x³-3x²+2x, then find the value of p(1)

Answer 1

p(1) = 1³ -3*1² +2*1
= 1 -3*1 +2
=1-3+2
= 3-3
= 0

Answer 2

$p(x) = {x}^{3} - 3 {x}^{2} + 2x \\ p(1) = {1}^{3} - 3 ({1})^{2} + 2(1) \\ \: \: \: \: \: \: \: \: \: = 1 - 3 + 2 = 0$