Question

If p(x) = x³ + 3x² + 3x + 1 , find the value of p (0) + p (-1) + p (2)​

Answer 1

Answer:

The value of p (0) + p (-1) + p (2)​ is 28

Step-by-step explanation:

p(x) = x³ + 3x² + 3x + 1

put p = 0

p(x) = x³ + 3x² + 3x + 1

p(0) = (0)³ + 3(0)² + 3(0) + 1

   = 0 + 0 + 0 + 1

   = 1

put p = -1

p(1) = (-1)³ + 3(-1)² + 3(-1) + 1

     = -1 + 3 -3 + 1

 = 0

put p = 2

p(2) = (2)³ + 3(2)² + 3(2) + 1

  = 8 + 3(4) + 6 + 1

  = 8 + 12 + 6 + 1

 =  27

now,

p (0) + p (-1) + p (2)​

1 + 0 + 27

= 28

Answer 2

Answer:

27

Step-by-step explanation:

if p(x) = x^3 + 3x^2 + 3x + 1 then,

put x= 0

p(0) = 0^3 +3*0^2 + 3*0 +1 = 1

put x= (-1)

p(-1) = (-1)^3 + 3 * (-1)^2 + 3 *(-1)

= -1 + 3 -3

= -1

put x = 2

p(2) = 2^3 + 3 * 2^2 + 3* 2 + 1

= 8 + 12 + 6 + 1

= 27

The value of (p) + p(-1) + p(2) is 27