If P(x) =x³ + 3x² + 5x -3
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Let p(x) =r + 13x? + 32x 20 Possible factors of 20 are = 1, +2, ± 4, + 5, + 10, + 20. We notice that p(-1) =-1+ 13 32 + 20 = 0 x=-1 is a zero of p(x) (x 1) is a factor of p(x). Let us divide p(x) by (x + 1) x + 12r + 20 *+1 )x' + 13x + 32x + 20 12x + 32r 12x + 12x 20x + 20 20x + 20 p(x)= x + 13x + 32x + 20 = (x+1) (x + 12r + 20) = (x+ 1) (x2 + 10x+ 2x+ 20) 1) {x(x + 10) + 2(x+ 10)} (x + 1) (x + 2) (x + 10)
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