Question

if p(x)=x3 +3x22 -2x +4 then find the value of p(2) +p(-2) -p(0)

Answer 1

Heya !!!

P(X) = X³+3X² -2X +4

P(2) = (2)³ + 3 × (2)² - 2 × 2 +4

=> 8 + 12 - 4 +4

=> 20

P(-2) = (-2)³ + 3 × (-2)² - 2 × -2 +4

=> -8 + 3 × 4 + 4 +4

=> -8 + 12 +4 +4

=> -8 + 20

=> 12

P(0) = (0)³ + 3 × (0)² - 2 × 0 +4

=> 0 + 0 - 0 +4

=> 4

Therefore,

P(2) + P(-2) - P(0)

=> 20 + 12 - 4

=> 32-4


=> 28.

HOPE IT WILL HELP YOU....... :-)

Answer 2

Heya

p(x) = x³+3x²-2x+4

p(2) = 2³ + 3 (2)² - 2(2) + 4

= 8 + 12 - 4 + 4

= 20

p(-2) = (-2)³+3(-2)²-2(-2)+4

= -8+12+4+4

= 12

p(0) = 0³+3(0)²-2(0)+4

= 4

p(2)+p(-2)-p(0) = 20+12-4

= 32-4

= 28

Hope it helps! ^_^