Math, asked by prjadhav2511, 1 month ago

If p(x)=(x³ + 4x – 5) is divided by (x-1) then find the remainder and hence determine
whether (x-1) is a factor of p(x) or not?​

Answers

Answered by hukam0685
0

Step-by-step explanation:

Given: If p(x) =  {x}^{3}  + 4x - 5 \\ is divided by (x - 1).

To find: Find the remainder and hence determine whether (x-1) is a factor of p(x) or not?

Solution:

Divide p(x) by (x - 1)

x - 1 \: )  \: {x}^{3}  + 4x - 5 \: ( {x}^{2} + x  + 5 \\  {x}^{3}  \:  \:  \:  \:  \:  \:  \:   \:   \: \:  -  {x}^{2}  \\  -  -  -  -  -  -  -  \\  {x}^{2}  + 4x - 5 \\  {x}^{2}  - x \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  -  -  -  -  -  \\ 5x - 5 \\ 5x - 5 \\  -  -  -  -  -  \\ 0 \\  -  -  -  -  -

Remainder is zero.

Thus,

(x - 1) \: is a factor of p(x).

Final answer:

If p(x)=( {x}^{3} +4x-5) is divided by ( x-1), then remainder is 0 and hence (x-1) is a factor of p(x) .

Hope it helps you.

To learn more on brainly:

If (x-2) is a factor of the polynomial x³-6x²+ax-8, then the value of a is

https://brainly.in/question/28133555

What is the remainder, if the polynomial x³+4x²+4x-3 is divided by x-1

a)5 b)-5 c)6 d)-6

https://brainly.in/question/47706240

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