Math, asked by palashmondal0, 6 months ago

If p(x) = x3 – 5x2 + 4x – 3 and g(x) = (x - 2), show that p(x)is not a
multipleof g(x).​

Answers

Answered by Ruhimahajan
1

Answer:

p(x)=x^3-5x^2+4x-3,g(x)=(x-2)

step1.x-2=0

x=2

now,put the x=2

p(2)=2^3-5(2)^2+4(2)

=8-20+8

=8-28

x =20 ans

hope it helps☺☺......

Answered by Anonymous
80

\underline{ \red {\bold{Solution:-}}}

g(x) = x - 2

⟹ x - 2 = 0

⟹ x = 2

Thus, now p(2) = x³ - 5x² + 4x - 3

We will subsitute the values instead of x as 2

Therefore,

⟹ (2)³ - 5(2)² + 4 × 2 - 3

⟹ 8 - 20 + 8 - 3

⟹ 16 - 23

⟹ 7

Thus, we got the value 7 which Isn't equal to 0

Hence, Proved

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