Question

if p(x)=x³+6x²+11x+6 then find 1.(p-1) and p(0) ​

Answer 1

$= > p(x) = {x}^{3} + 6 {x}^{2} + 11x + 6$

1.

$= > p( - 1) = {( - 1)}^{3} + 6 { (- 1)}^{2} + 11 \times ( - 1) + 6$

$= > p( -1 ) = - 1 + 6 - 11 + 6$

$= > p( - 1) = 0$

2.

$= > p(0) = {(0)}^{3} + 6 {(0)}^{2} + 11 \times (0) + 6$

$= > p(0) = 0 + 0 + 0 + 6$

$= > p(0) = 6$

Hope this answer helps you ^_^ !