Question

If p(x) = x3 + 7x + 3, q(x) = x2 + x -12 and r(x) = x-3, then find the degree of

p(x)q(x)r(x)​

Answer 1

Answer:

Degree of p(x) = 3

Degree of q(x) = 2

Degree of r(x) = 1

Answer 2

p(x) = x³ + 7x + 3, degree is 3.

q(x) = x² + x - 12, degree is 2.

r(x) = x - 3, degree is 1.

Clearly, the highest term of p(x)q(x)r(x) is

x³ × x² × x

$= {x}^{3 + 2 + 1} = {x}^{6}$

So, degree of p(x)q(x)r(x) is 6.