Question

If p(x)=x3+8x2-8x+9 find p(0),p(1)

Answer 1

Answer:

$p(0) = 9 \\ \\ p(1) = 10$

Step-by-step explanation:

$p(x) = {x}^{3} + 8 {x}^{2} - 8x + 9 \\ \\ p(0) = 0 + 0 - 0 + 9 \\ p(0) = 9 \\ \\ \\ p( 1) = 1 + 8 - 8 + 9 \\ p(1) = 10$