Math, asked by yuvi9999, 1 year ago


If p(x) = x3 - ax2 + 2x + a - 1 and p(a) = 0, then find the value of a.​

Answers

Answered by Anonymous
2

Answer:

P(a) = (a³)-a(a)²+2a+a-1

0 = a³-a³+3a-1

3a-1 = 0

3a = 1

a = 1/3

Answered by FeluMitter
2

Answer:

\frac{1}{3}

Step-by-step explanation:

p(x)=x^3-ax^2+2x+a-1\\p(a)=a^3-a(a)^2+2(a)+a-1\\0=3a-1\\a=\frac{1}{3}

Similar questions