if p(x)=x³+x²-2x+4 then find the value of p(2)+p(-2)-p(0)
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Answer:
P(x) = x³ + 3x² - 2x + 4
P(2) = 2³ + 3(2)² - 2(2) + 4
= 8+3(4)-4+4
= 8+12-4+4
= 20
P(-2) = (-2)³ + 3(-2)² - 2(-2) + 4
= -8+3(4)+4+4
= -8+12+8
= 12
P(0) = 0³+3(0)²-2(0)+4
= 0+0-0+4
= 4
P(2) + P(-2) - P(0) = 20 + 12 - 4
= 32 - 4
= 28
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