If p(x)= x³- x²+ 3x+ 1 ; then find the value of p(1) and p(-1)
Answers
Answered by
0
Answer:
REFER TO THE ATTACHED PIC FOR UR ANSWER....
HOPE IT HELPS. PLS MARK ME BRAINLIEST✌
Attachments:
Answered by
4
Given :
Given that, p(x) = x³ - x² + 3x + 1.
To find :
We should find the value of p(x) when p(1) and p(-1).
Solution :
Substituting p(1) in p(x) = x³ - x² + 3x + 1:
- x³ - x² + 3x + 1
- (1)³ - (1)² + 3(1) + 1
- 1 - 1 + 3 + 1
- 0 + 3 + 1
- 4
Substituting p(-1) in p(x) = x³ - x² + 3x + 1
- x³ - x² + 3x + 1
- (-1)³ - (-1)² + 3(-1) + 1
- -1 - (1) - 3 + 1
- - 1 - 1 - 3 + 1
- 0 - 1 - 3
- - 4
_________________________
Therefore, the values of p(x)=x³-x²+3x+1 when p(1) and p(-1) are 4 and -4 respectively.
Similar questions