Math, asked by baburajdevan, 1 month ago

If p(x)= x³- x²+ 3x+ 1 ; then find the value of p(1) and p(-1)​

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Answered by Sreyashpedia
0

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Answered by VεnusVεronίcα
4

Given :

Given that, p(x) = x³ - x² + 3x + 1.

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To find :

We should find the value of p(x) when p(1) and p(-1).

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Solution :

Substituting p(1) in p(x) = x³ - x² + 3x + 1:

  • x³ - x² + 3x + 1
  • (1)³ - (1)² + 3(1) + 1
  • 1 - 1 + 3 + 1
  • 0 + 3 + 1
  • 4

Substituting p(-1) in p(x) = x³ - x² + 3x + 1

  • x³ - x² + 3x + 1
  • (-1)³ - (-1)² + 3(-1) + 1
  • -1 - (1) - 3 + 1
  • - 1 - 1 - 3 + 1
  • 0 - 1 - 3
  • - 4

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Therefore, the values of p(x)=-x²+3x+1 when p(1) and p(-1) are 4 and -4 respectively.

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