Math, asked by gursimran4970, 15 days ago

if p (x)=x³-x²+x+1, find the value of p(-1)​

Answers

Answered by drzeeshanawwab
1

Step-by-step explanation:

p(x) = x³-x²+x+1

Putting x=-1

p(-1) = (-1)³-(-1)²+(-1)+1

= -1-1-1+1

= -2

therefore, p(-1) = -2

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