if p(x)=x³-x²+x+1, then find the value of p(1)+p(-1)
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Step-by-step explanation:
p(x) = x³ - x² + x + 1
p(1) = 1 - 1 + 1 + 1 = 2
p(-1) = -1 - 1 - 1 + 1 = -2
So , p(1) + p(-1) = 2 +(-2) = 2-2 = 0
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