Question

If p(x) = x³-x²+x+1, then find the value of p (1)+p(-1)+p(2)/2​

Answer 1

Answer:

p(x)=x³‐x²+x+1

p1=1³‐1²+1+1

=1‐1+1+1

=1+1

=2

p(‐1) =(-1)³‐(‐1)²+(‐1)+1

=‐1-1-1+1

=‐1‐1

=‐2

p(2)=2³‐2²+2+1

=8‐4+2+1

=4+3

=7

p(1)+p(‐1)+p(2)/2

=(2)+(-2)+(7)/2

=2‐2+7/2

=7/2

the answer of p(1)+p(‐1)+p(2)/2 is 7/2