Question

if p(x)=x³-x²+x+1,then value of p(-) + p(1)/2 is​

Answer 1

Answer:

Given p(x) = x³-x²+x+1,

We need to find the value of 1/2[p(-1) + p(1)]

Consider p(-1) = (-1)³ - (-1)² -1 + 1

= -1 -1 -1 + 1

= -2

Consider p(1) = 1³ - 1² + 1 + 1

= 1 - 1 + 1 + 1

= 2

So, p(-1) + p(1)

= -2 + 2

= 0

Hence, 1/2[p(-1) + p(1)] = 1/2*0

= 0.

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