Question

If P(X) = X⁴ + 2x³-3x²+x , find p(1)+(p-1)​

Answer 1

Step-by-step explanation:

$p( - 2) = {( - 2)}^{4} + 2 { (- 2)}^{3} - 3 {( - 2)}^{3} - ( - 2) - 1 \: \: \: \: \: \: \: \: \: \: = 16 - 16 + 12 - 10 + 8 \: \: \: \: = 10$

Answer 2

Answer:

tep explanation:

p( - 2) = {( - 2)}^{4} + 2 { (- 2)}^{3} - 3 {( - 2)}^{3} - ( - 2) - 1 \: \: \: \: \: \: \: \: \: \: = 16 - 16 + 12 - 10 + 8 \: \: \: \: = 10p(−2)=(−2)

4

+2(−2)

3

−3(−2)

3

−(−2)−1=16−16+12−10+8=10