Question

If p(x)=xsquare-1 then find p(-1)

Answer 1

$\huge\underline\mathtt\pink{Answer}$

$p(x) = {x}^{2} - 1 \\ p( - 1) = ( { - 1)}^{2} - 1 \\ \: \: \:\: \: \: = 1 - 1 \\ p( - 1) = 0$

Answer 2

$\huge\bf\purple{Answer:}$

$\large\bf\purple{To~solve:}$

$\tt{p(x)=x^{2}-1~~~~{\bf{when}},~x=-1}$

$\tt{~~~~~~~~~~~~~p(x)=x^{2}-1}$

$\tt{= \implies p(-1)=(-1)^{2}-1}$

$\tt{= \implies 1-1}$

$\tt{= \implies {\underline{\boxed{\tt~~0~~}}}}$

$\huge\sf\purple{Hope~it~helps..!!}$