Question

if p(x)=xsquare-4x+3 find the value of p(-1),p(0),p(1),p(2)​

Answer 1

Answer:

p(-1) = (-1)² - 4(-1) + 3

= 1 + 4 + 3

= 8

p(0) = (0)² - 4(0) + 3

= 0 - 0 + 3

= 3

p(1) = (1)² - 4(1) + 3

= 1 - 4 + 3

= 0

p(2) = (2)² - 4(2) + 3

= 4 - 8 + 3

= -1

Answer 2

Answer:

Given:-

$p(x) = {x}^{2} - 4x + 3$

Find:-

Value of P

Solution:-

Value of P when P(0)

$p(0) = {0}^{2} - 4(0) + 3 \\ = 0 - 0 + 3 \\ = 3$

Value of P when P(-1)

$p( - 1) = {( - 1)}^{2} - 4( - 1) + 3 \\ = 1 + 4 + 3 \\ = 5 + 3 \\ = 8$

Value of P when P(1)

$p(1) = {1}^{2} - 4(1) + 3 \\ = 1 - 4 + 3 \\ = - 3 + 3 \\ = 0$

Value of P when P(2)

$p(2) = {(2)}^{2} - 4(2) + 3 \\ = 4 - 8 + 3 \\ = - 4 + 3 \\ = - 1$

Hope it's helpful ❣