Question

If P(x, y) is a point equidistant from the points A(3, 4) and B(7, -2) then find

the relation between x and y.​

Answer 1

Answer:

(PA)2=(PB)2

(x-3)2+(y-4)2 = (x-7)2 + (y+2)2

X2+9-6x+y2+16-8y=X2+49-14x+y2+4+4y

9-6x+16-8y = 49-14x+4+4y

-6x-8y +14y-4x= 53-25

-10x + 6y = 28

(6y-10x=28) divided the equation by 2

3y-5x=14

thanks...........