If P(x,y) is a point equidistant from the points A(6,-1) and B(2,3) show that x-y =3
Answers
Answered by
42
given PA=PB(equidistant from the points A(6,-1))and B(2,3))
squaring on both sides
(PA)^2=(PB)^2
(x-6)^2+(y+1)^2=(2-x)^2+(3-y)^2
x2+36-12x+y2+1+2y=x2+4-4x+9+y2-6y
8x-8y = 8(3)
x-y = 3
Hence it is showed that x-y=3.
squaring on both sides
(PA)^2=(PB)^2
(x-6)^2+(y+1)^2=(2-x)^2+(3-y)^2
x2+36-12x+y2+1+2y=x2+4-4x+9+y2-6y
8x-8y = 8(3)
x-y = 3
Hence it is showed that x-y=3.
Answered by
4
Step-by-step explanation:
hope it will hlp you alll guys......
Attachments:
Similar questions