if p(x y) is a point equidistant from the points a(6 -1) and b(2 3) show that x-y=3
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Given, ap = bp
=> (ap)² = (bp)²
=> [√(6-x)²+ (-1-y)²]² = [√(2-x)²+(3-y)²]²
=> (6-x)²+ (-1-y)² = (2-x)²+(3-y)²
By simplifying,
x-y = 3
Hence proved
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