If P(x , y) is any point on the line joining the points A (a , 0) and B(0 , b) , then show that
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If a point (x,y) lies on a line joining the points A(x₁,y₁) and B(x₂,y₂), the equation of the line is given by
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Point P(x,y) lies on the line joining the points A(a,0) and B(0,b). So

Point P(x,y) lies on the line joining the points A(a,0) and B(0,b). So
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